Hello!
As you can see, C is the cost of each uniform. This would give us the equation below, if each uniform was $60.
60=40n+260/n
Let's multiply both sides by n.
60n=40n+260
Now, let's subtract 40n from both sides.
20n=260
We divide both sides by 20.
n=13
Therefore, 13 uniforms were purchased.
I hope this helps!
ja, yo is correct, just expand that formula with your calculator
each one is 5% bigger than pevious
each one=previous+previous*5%
each one=previous*1+previous*0.05
each one=previous*(1+0.05)
each one is 1.05 times of previous
so after n years, if today year size is P then
A=final size
so ya, after 18 years, n=18 so you get
A=2067.29 microliters
The perimeter =14 in
The area =64cm
90 round to the nearest hundredth
Answer:
$23.88
Step-by-step explanation:
Represent the original price by p.
The sale price is (100% - 60%), or 40%, of p:
$9.55 = 0.40p
Dividing both sides by 0.40 results in:
p = $23.88 (rounded up from $23.875).
