The value of

,

, and

for each schools is given in the first picture below.

is the lower quartile

is the median

is the upper quartile
School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5
School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18
The box plot for each school is shown in the second picture
Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left
There are 64 people in the room.
Since the ratio for women increases 1 when 8 women enter the room, for every time there is 1 in the ratio there are 8 people. That means that originally you have to do 3x8 and 4x8. You get 24 and 32 which equals 56. Then when 8 more women enter the room, you get 64.
The weight of each cabbage is not given.
I'll assume that each cabbage weighs p pounds.
Now, we know that Yasmin bought 6 cabbage each weighing p pounds. To know the total weight, we will simply multiply the number of cabbages by the weight of each as follows:
Total weight = 6 * p = 6p pounds
Hope this helps :)
Answer:
Reject H0 since test statistic <-2.492
Step-by-step explanation:
Given that the American Water Works Association reports that the per capita water use in a single-family home is 74 gallons per day.
n = 25
x bar = 69
s= 8.3
std error = s/sqrt n = 
H0:
Ha: 
(Left tailed test at 5% significance level)
a) Reject H0 if t
-2.492
b) Test statistic = mean difference/std error
= 
=-3.01
df =24
c) Reject H0
Answer:
4 i think
Step-by-step explanation: