Question

jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to travel to town B. He drove at an average speed of 100 km/h. At what time will Sipho catch up jabu?​

Answer 1

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

$J(t) = 200 + 80t$

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

$S(t) = 100t$

At what time will Sipho catch up jabu?​

He will catch up in t hours, and t is found when:

$S(t) = J(t)$

So

$100t = 200 + 80t$

$20t = 200$

$t = \frac{200}{20} = 10$

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm