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svlad2 [7]
3 years ago
15

8(-6a+2)+(-5)(-9a+2)

Mathematics
2 answers:
Anika [276]3 years ago
7 0
<span><span>−3a+6</span><span> would be your answer could you please mark as the brainliest???</span></span>
RUDIKE [14]3 years ago
4 0
Well 1st do the -48a (t) 2
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On his first three tests, Shaun scored 88, 98, and 79. What score must he get on his fourth test to have an average (mean) of 80
solniwko [45]

Answer:

Step-by-step explanation:

let score in fourth test=x

88+98+79+x=80×4

265+x=320

x=320-265=55

7 0
3 years ago
Set up the equation to find the AREA of the SMALL rectangle with a length of (x) and width (x+7)
Igoryamba

<u>Answer:</u>

<h3>( x ) x ( x + 7 ) </h3>

<u>Step-by-step explanation:</u>

To find the area of a rectangle, we have to multiply the length with the width.

In the question, the given length is 'x' and the width given is 'x +7'

So, the area would be

( x ) x ( x + 7 )

The area = x^{2} + 7x

So, the equation to find the area of such a rectangle would be:-

( x ) x ( x + 7 )

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3 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Marina CMI [18]

Answer:2


Step-by-step explanation: two ones equal one two


8 0
3 years ago
What is the answer of y=2x?<br>​
PIT_PIT [208]

Answer:

x = 0

Step-by-step explanation:

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3 0
3 years ago
In the following pair of polynomials, the second polynomial is a factor of the first. Factor completely x^3+3x^2-18x , x-4
OLga [1]

Answer:

The required factors are: x, (x + 6) and (x - 3).

Step-by-step explanation:

As per the question,

The given polynomial is:

x^{3}+3x^{2}-18x

Now,

BY factorization, we get

x^{3}+3x^{2}-18x

=x(x^{2}+3x-18)

By splitting the mid-term, that is split 3x like:

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x(x^{2}+6x-3x-18)

Now on further solving by taking common factor out, we get

=x[x(x+6)-3(x+6)]

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Therefore, the given second polynomial (x - 4), is not a factor of given polynomial x^{3}+3x^{2}-18x.

Hence, the given polynomial has three factor x, (x + 6) and (x - 3).

8 0
3 years ago
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