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adoni [48]
3 years ago
14

Examine the diagram. It is not drawn to scale.

Mathematics
1 answer:
konstantin123 [22]3 years ago
8 0

Answer:  I estimate that it is 119

Step-by-step explanation:

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HELP ME PLEASE!!!!<br> ΔAXY ~ ΔABC. What is the value of BC
emmasim [6.3K]

Answer:

BC = 28 \frac{1}{3} ft

Step-by-step explanation:

Given that the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{AX}{AB} = \frac{XY}{BC} , substitute values

\frac{12}{20} = \frac{17}{BC} ( cross- multiply )

12BC = 340 ( divide both sides by 12 )

BC = \frac{340}{12} = \frac{85}{3} = 28 \frac{1}{3}

6 0
3 years ago
4x-y=10 as coordinates with the y as -6
IgorC [24]

Answer:

(1,-6)

Step-by-step explanation:

4x - y = 10

4x -(-6) = 10

4x + 6 = 10

    - 6    - 6

4x = 4

/4    /4

x = 1

(x, y) -> (1,-6)

Check your answer:

4x - y = 10

4(1) - (-6) = 10

4 + 6 = 10

10 = 10

This statement is correct

Hope this helps!

6 0
2 years ago
Read 2 more answers
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
2 years ago
Please help me on this question I would highly appreciate it please
MrRa [10]
Two plus nine-teen is twenty one then you subtract seven from that and get fourteen. Your answer is 14 foot
7 0
3 years ago
Read 2 more answers
Javier is 175% heavier than his brother. If Javier’s brother weighs 80 pounds, how much does Javier weigh?
bija089 [108]

Answer:

140

Step-by-step explanation:

175% of 80 = 140

7 0
3 years ago
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