All categories

3 years ago

What happens to the volume of a sphere when its diameter is tripled?

1 answer:

8 0

V = 4/3 pi r^3

r is directly proportional to the diameter

and v is proportional to r^3

so

v is proportional to d^3

for d tripled

v is (3)^3 = 27 times original

You might be interested in

Find the length. Round your answer to the nearest tenth

Yuri [45]

C it’s the answer I think maybe

6 0

3 years ago

A toy company had an order of five boxes to ship unfortunately this was 17 pounds over the shipping weight limit per order of ea

pochemuha

Answer:

28 pounds

Step-by-step explanation:

We have a total of 5 boxes, now we know that each box weighs 9 pounds, therefore:

Total weight = 5 * 9 = 45 pounds

Which means there are 45 pounds in total.

We are told that the limit is exceeded by 17 pounds. To find the limit weight, it is necessary to subtract the total weight and the excess:

45-17 = 28 pounds

Therefore, the maximum weight allowed per shipment is 28 pounds.

6 0

3 years ago

Write your answer in simplest radical form

Varvara68 [4.7K]

Answer:

n = 8√2

Step-by-step explanation:

It's a 30-60-90 triangle, so n = 2×4√6/√3 = 8√2

6 0

2 years ago

D Evaluate arcsin (6)] at x = 4. dx

sineoko [7]

Answer:

$\frac{1}{2\sqrt{5} }$

Step-by-step explanation:

Let, $\text{sin}^{-1}(\frac{x}{6})$ = y

sin(y) = $\frac{x}{6}$

$\frac{d}{dx}\text{sin(y)}=\frac{d}{dx}(\frac{x}{6})$

$\frac{d}{dx}\text{sin(y)}=\frac{1}{6}$

$\frac{d}{dx}\text{sin(y)}=\text{cos}(y)\frac{dy}{dx}$ ---------(1)

$\frac{1}{6}=\text{cos}(y)\frac{dy}{dx}$

$\frac{dy}{dx}=\frac{1}{6\text{cos(y)}}$

cos(y) = $\sqrt{1-\text{sin}^{2}(y) }$

= $\sqrt{1-(\frac{x}{6})^2}$

= $\sqrt{1-(\frac{x^2}{36})}$

Therefore, from equation (1),

$\frac{dy}{dx}=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

Or $\frac{d}{dx}[\text{sin}^{-1}(\frac{x}{6})]=\frac{1}{6\sqrt{1-\frac{x^2}{36}}}$

At x = 4,

$\frac{d}{dx}[\text{sin}^{-1}(\frac{4}{6})]=\frac{1}{6\sqrt{1-\frac{4^2}{36}}}$

$\frac{d}{dx}[\text{sin}^{-1}(\frac{2}{3})]=\frac{1}{6\sqrt{1-\frac{16}{36}}}$

$=\frac{1}{6\sqrt{\frac{36-16}{36}}}$

$=\frac{1}{6\sqrt{\frac{20}{36} }}$

$=\frac{1}{\sqrt{20}}$

$=\frac{1}{2\sqrt{5}}$

4 0

2 years ago

PLZ HELP WILL MARK BRAINLEST +10 POINTS

mixas84 [53]

Answer:

It's C

The X and Y coordinates are both negative

Step-by-step explanation:

Quadrant 1- negative and positive

Quadrant 2- positive and positive

Quadrant 3- negative and negative

Quadrant 4-positive and negative

7 0

2 years ago