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3 years ago

Choose the product.

1 answer:

4 0

(5x² + 2x - 3)(x - 1)
= 5x³ - 5x² + 2x² - 2x - 3x + 3
= 5x³ - 3x² - 5x + 3

In short, Your Answer would be Option D

Hope this helps!

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10 1/2 I am pretty sure its right

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3 years ago

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Likurg_2 [28]

Answer:

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Step-by-step explanation:

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3 years ago

Please help me solve

mihalych1998 [28]

Answer:

x = 36.3°

using tane rule:

$\sf tan(x)= \dfrac{opposite}{adjacent}$

Here!

x = missing angle

opposite = 22

adjacent = 30

=============

$\hookrightarrow \sf tan(x) = \dfrac{22}{30}$

$\hookrightarrow \sf x= tan^{-1}(\dfrac{22}{30} )$

$\hookrightarrow \sf x= 36.253^{\circ \:}$

$\hookrightarrow \sf x= 36.3^{\circ \:}$ ( rounded to nearest tenth of a degree)

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3 years ago

Read 2 more answers

Stock A ‘s returns have a standard deviation of 0.5, and stock B’s returns have standard deviation of 0.6.The correlation coeffi

galben [10]

Answer:

The variance of the profile is 0.2179.

Step-by-step explanation:

We are given the following in the question:

$\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3$

Variance of portfolio is given by:

$w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}$

$Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15$

Putting values, we get,

$w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179$

Thus, the variance of the profile is 0.2179.

4 0

3 years ago

Casper has some whipping cream that is 18%, percent butterfat, and some milk that is %4, percent butterfat. He wants to make a 5

steposvetlana [31]

L represent Option A. The correct answer is that the mixture has the intended volume and has more than the intended percent of butterfat.

<h3>What is the graph about?</h3>

Note that:

The graph shows that the point L is one that is below the blue line of the graph.

Therefore, x + y = 500

Also one need to see that:

0.18x + 0.04y = 500(0.12)

Since that cream is 18% butterfat, milk is 4% butterfat, so L is composed of of 350 ml of cream and 100 ml of milk.

Hence the total amount of butterfat for L is:

0.18 x 350 + 0.04 x 100

= 67ml.

Next, one has to calculate 12% of the volume of L :

12% of 450:

0.12 x 450 = 54ml

So, because 67 is bigger than 54, this implies that the volume of butter fat in L is more than 12 %.