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goldenfox [79]
3 years ago
10

Is a good economist always objective or

Mathematics
1 answer:
Mashutka [201]3 years ago
3 0

anwer

yes good economist is always objective.

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The measure of the exterior angle of the triangle is what degree?
RSB [31]

Answer:

92°

Step-by-step explanation:

By exterior angle theorem:

(2x - 2) \degree = x \degree + 45 \degree \\  \\ (2x - 2 - x) \degree = 45 \degree \\  \\ (x - 2) \degree = 45 \degree \\  \\ (x - 2)  = 45 \\  \\ x = 45 + 2 \\  \\ x = 47 \\  \\ (2x - 2) \degree  = (2 \times 47 - 2)\degree  \\  \\ (2x - 2) \degree  = (94 - 2)\degree   \\  \\ (2x - 2) \degree  = 92\degree   \\  \\ measure  \: of  \: the  \: exterior \:  angle \\  = 92 \degree

4 0
3 years ago
Which equation matches the statement below?
kvasek [131]

Answer:

3(n-5)=2n+16

Step-by-step explanation:

3 lots of 'n' <em>and </em>5 means 3 times both values so these values are put into a bracket with a common multiplier (ie. the 3)

3(5 - n)

16 more than 2 lots of 'n' means that n has to be doubled. n + n = 2n. add 16 to this and we have

2n + 16

if these values are both equal (hence why they are in an equation) then all that is needed is for them to be set equal alongside each other.

3(n-5) = 2n+16

:)

8 0
2 years ago
During a middle school basketball ​game, every spectator placed his or her ticket stub into one of several containers. After the
Fofino [41]

Answer:

The eight people to march in a sportsmanship parade.

Step-by-step explanation:

6 0
3 years ago
6. Regroup the numbers in the following problems, putting the numbers that add up to 10 or a multiple of 10 in parentheses.
svetoff [14.1K]

Answer:

a) (2+8)+9

b) (3+7)+5+4

c) (4+16)+2

d) (31+9)+4

Step-by-step explanation:

a) 2+9+8

2 and 8 add up to 10, so we regroup them in parentheses

(2+8)+9


b) 3 + 5 + 4 + 7

3 and 7 add up to 10, so we regroup them in parentheses

(3+7)+5+4


c) 4 + 2 + 16

4 and 16 add up to 20 which is a multiple of 10, so we regroup them in parentheses

(4+16)+2


d) 31 + 4 + 9

31 and 9 add up to 40 which is a multiple of 10, so we regroup them in parentheses

(31+9)+4

4 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
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