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Fudgin [204]
4 years ago
14

Use the substitution method to solve the system of equations.

Mathematics
1 answer:
Ipatiy [6.2K]4 years ago
4 0
Substitute y = x - 8 for y in 2x + 3y = 1:
2x + 3(x - 8) = 1
2x + 3x - 24 = 1
5x - 24 = 1
5x = 25
x =  5
Substitute 5 for x in y = x - 8 and 2x + 3y = 1
y = 5 - 8 --> y = -3
2(5) + 3y = 1 --> 10 + 3y = 1 --> 3y = -9 --> y = -3
x = 5 and y = -3
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fridays high temp was -1. the low temp was -5. what was the difference between the high and low temps
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the graph of f(x)=|x| is shown below. If you vertically shift this function down 11 units, what is the equation of the new funct
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3 years ago
The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a
enot [183]

Answer:

a) \bar X =\frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

b) The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s= 0.0206

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma=0.0188

Step-by-step explanation:

For this case we have the following dataset:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

And if we replace we got:

\bar X =\frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s= 0.0206

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma=0.0188

5 0
4 years ago
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