Does anybody know the answer???
1 answer:
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Answer:
The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.
Step-by-step explanation:
Given:
Coin is tossed and a single 6 sided number cube is rolled.
Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.
Now, we know that:
Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes
Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.
So, probability of event 'H' is given as:
Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is,
Now, probability of rolling a 3 is given as:
Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,
Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.
Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.
Answer:
400 units³
Step-by-step explanation:
The volume (V) of the square pyramid is
V = area of base × height (h)
where h is the perpendicular height.
Consider the right triangle formed by a segment from the vertex to the midpoint of the base and the slant height ( the hypotenuse )
Using Pythagoras' identity on the right triangle
h² + 5² = 13²
h² + 25 = 169 ( subtract 25 from both sides )
h² = 144 ( take the square root of both sides )
h = = 12
Area of square base = 10² = 100, hence
V = × 100 × 12 = 4 × 100 = 400