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3 years ago

Find the area of the triangle.

Mathematics

1 answer:

Ne4ueva [31]3 years ago

5 0

Answer:

10.92cm

Step-by-step explanation:

We can solve this problem by taking the formula to the area of a triangle and substituting our given numbers with the variables in it.

$A = \frac{1}{2}bh$ , where $b$ represents base and $h$ represents height.

So, if we substitute our given measurements with the variables in this formula, we can easily solve this.

$A = \frac{1}{2}(2.8)(7.8)$

Then, using the order of operations, we multiply and ultimately solve this problem.

$\frac{1}{2}*2.8 = 1.4$

$1.4*7.8=10.92$

Thus, our answer is 10.92cm.

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Men consume on average 15 grams of protein a day. Assume a normal distribution with a standard deviation of 3 grams. A sample of

tatyana61 [14]

Using the normal distribution, there is a 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For this problem, the parameters are given as follows:

$\mu = 15, \sigma = 3, n = 40, s = \frac{3}{\sqrt{40}} = 0.4743$

The probability is the <u>p-value of Z when X = 16 subtracted by the p-value of Z when X = 15</u>, hence:

X = 16:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{16 - 15}{0.4743}$

Z = 2.11

Z = 2.11 has a p-value of 0.9826.

X = 15:

$Z = \frac{X - \mu}{s}$

$Z = \frac{15 - 15}{0.4743}$

Z = 0

Z = 0 has a p-value of 0.5.

0.9826 - 0.5 = 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

More can be learned about the normal distribution at brainly.com/question/15181104

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2 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$