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3 years ago

Identify the appropriate equation to solve for this diagram

Mathematics

1 answer:

ahrayia [7]3 years ago

4 0

Answer:

Step-by-step explanation:

bcssjtsnsgnzjgdnydjts

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Can someone help mme

Vanyuwa [196]

Answer:

ok this is that and that is this.hope this helps

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2 years ago

HELP PLSSS THIS IS HARD SOMEONE

Oduvanchick [21]

Answer:

scale factor is 3, k=3

Step-by-step explanation:

everything is being multiplied by 3

3 0

3 years ago

What is the value of h in this graph ?<br> F(x)= |x - h|

Misha Larkins [42]

Answer:

$h=4$

Step-by-step explanation:

We know that the vertex(lowest point) of $|x-h|$ is $(h, 0)$ .

By inspection, we can see that the vertex of the graph is $(4, 0)$ .

So, the lowest point of $F(x)=|x-h|$ is $(4, 0)$ , which means $\boxed{h=4}$

8 0

2 years ago

Read 2 more answers

Can some one help pls

arlik [135]

Answer: <DEF & <JKL

Step-by-step explanation:

they equal 90 degrees

complementary angles equal 90 degrees

8 0

2 years ago

Read 2 more answers

At what angle does a diffraction grating produce a second-order maximum for light having a first-order maximum at 20.0 degrees?

hichkok12 [17]

Answer:

At 43.2°.

Step-by-step explanation:

To find the angle we need to use the following equation:

$d*sin(\theta) = m\lambda$

Where:

d: is the separation of the grating

m: is the order of the maximum

λ: is the wavelength

θ: is the angle

At the first-order maximum (m=1) at 20.0 degrees we have:

$\frac{\lambda}{d} = \frac{sin(\theta)}{m} = \frac{sin(20.0)}{1} = 0.342$

Now, to produce a second-order maximum (m=2) the angle must be:

$sin(\theta) = \frac{\lambda}{d}*m$

$\theta = arcsin(\frac{\lambda}{d}*m) = arcsin(0.342*2) = 43.2 ^{\circ}$

Therefore, the diffraction grating will produce a second-order maximum for the light at 43.2°.

I hope it helps you!

6 0

3 years ago