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dexar [7]
3 years ago
11

Identify the appropriate equation to solve for this diagram

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

b

Step-by-step explanation:

bcssjtsnsgnzjgdnydjts

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Find two equivalent fractions for 2/12
Gwar [14]
1/6 (divide each by 2)
4/24 (multiply each by 2)
8 0
3 years ago
Read 2 more answers
R: 7x - 2y = 14<br> each line<br> Slope
Llana [10]

Answer:

m=7/2

Step-by-step explanation:

7x-2y=14

2y=7x-14

y=7/2x-14/2

y=7/2x-7

y=mx+b where m=slope and b=y-intercept,

the slope is 7/2

7 0
3 years ago
If
Nitella [24]

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

<h3>How to find the production level that'll maximize profit?</h3>

The cost function, C(x) is given by 12000 + 400x − 2.6x² + 0.004x³ while the demand function, P(x) is given by 1600 − 8x.

Next, we would differentiate the cost function, C(x) to derive the marginal cost:

C(x) = 12000 + 400x − 2.6x² + 0.004x³

C'(x) = 400 − 5.2x + 0.012x².

Also, revenue, R(x) = x × P(x)

Revenue, R(x) = x(1600 − 8x)

Revenue, R(x) = 1600x − 8x²

Next, we would differentiate the revenue function to derive the marginal revenue:

R'(x) = 1600 - 8x

At maximum profit, the marginal revenue is equal to the marginal cost:

1600 - 8x = 400 − 5.2x + 0.012x

1600 - 8x - 400 + 5.2x - 0.012x² = 0

1200 - 2.8x - 0.012x² = 0

0.012x² + 2.8x - 1200 = 0

Solving by using the quadratic equation, we have:

x = 220.40 or x = -453.73.

Since profit can't be negative, the production level that'll maximize profit is approximately equal to 220.

Read more on maximized profit here: brainly.com/question/13800671

#SPJ1

6 0
2 years ago
Please help ASAP. I really need this it is almost due. Please give me the right answer.
IceJOKER [234]
A and D
Put 3 in the equations and solve
5 0
3 years ago
the taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km,
Olegator [25]

Answer:

255

Step-by-step explanation:

total cost paid = fixed cost + total variable cost

total variable cost = distance travelled x variable cost per unit

two equations can be derived from the question

a + 10b = 105  equation 1

a + 15b = 155   equation 2

a = fixed cost

b =  variable cost per unit

Subtract equation 1 from 2

5b = 50

b = 10

Substitute for b in equation 1

a + 10(10) = 105

a = 105 - 100 = 5

a = 5

cost of travelling a distance of 25km

5 + 10(25) = 255

3 0
3 years ago
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