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3 years ago

Identify the appropriate equation to solve for this diagram

Mathematics

1 answer:

ahrayia [7]3 years ago

4 0

Answer:

Step-by-step explanation:

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The number of guests per month at a large resort is given in the table below, where f(x) is the number of guests, in hundreds, x

Solnce55 [7]

X = 0 ; y = 10 ; 10 = a(0) + b(0) + c
c = 10

x=2 ; y = 15 ; 15 = a(4) + b(2) + 10 ; 5 = 4a+2b
x=4 ; y=18 ; 18 = a(16) + b(4) + 10 ; 8 = 16a + 4b

2(5) = (4a+2b)2
-
<u> 8 = 16a + 4b
</u> 2 = -8a

a = -0.25

b = 2

y = (1/4)x^2 + 2x + 10 ; 4y = x^2 + 8x + 40

8 0

3 years ago

Read 2 more answers

0.8% of 150 is what numbers and how do you write the equation with a variable in it.

Tanzania [10]

Answer:

1.2

Step-by-step explanation:

1. First, we have to write an equation with a variable! Given 0.8%, we know that it's equal to (0.8/100), and "of" means to multiply. Therefore, the equation will looks like this: $\frac{0.8}{100} * 150 = x$

2. Now, let's solve for x!

$\frac{0.8}{100} * 150 = (0.008)(150)$
$(0.008)(150) = \frac{6}{5}$
$\frac{6}{5} = 1\frac{1}{5}$
$1\frac{1}{5} = 1.2$
$1.2$

Therefore, 0.8% of 150 is 1.2!

6 0

3 years ago

What type of function best models the data in the graph?

a_sh-v [17]

Answer: 1.)Quadratic

2.) A.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe

Allushta [10]

A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

(0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

(0.120 x $0.20 / hour) =

$0.024 / hour = <span>2.4¢ per hour </span>

5 0

3 years ago

A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical (ha

Neko [114]

Answer:

Volume: $\frac{2}{3}\pi r^3$

Ratio: $\frac{2}{9}r$

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

$V=\frac{4}{3}\pi r^3$

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

$V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3$

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

$A=4 \pi r^2$

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so $2\pi r^2$ . Moreover, we have to add the surface of the base, which is $\pi r^2$ . So the total surface area of the hemispherical tank is

$A'=2\pi r^2 + \pi r^2 = 3 \pi r^2$

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

$\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r$

6 0

3 years ago