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3 years ago

What is the slope-intercept equation of the line going through (-2,5) and (1,-1)?

Mathematics

1 answer:

jarptica [38.1K]3 years ago

3 0

Answer:

y = -2x+1

Step-by-step explanation:

The slope is found by

m = (y2-y1)/(x2-x1)

= (-1-5)/(1--2)

= -6/(1+2)

= -6/3

= -2

Then we can use point slope form to make an equation

y-y1 = m(x-x1)

y-5 = -2(x--2)

y-5 = -2(x+2)

Distribute

y-5 = -2x -4

Add 5 to each side

y-5+5 = -2x-4+5

y = -2x+1

This is in point slope form

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Answer:

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Step-by-step explanation:

step 1

Find the slope of the perpendicular line

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal

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In this problem

we have

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step 2

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we have

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substitute

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Convert to slope intercept form

$y=mx+b$

Distribute right side

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3 years ago

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