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viva [34]
3 years ago
11

If the radius of a cylinder was shrunk down to a quarter of its orignal size and the height was reduced to a third of its origin

al size, what would be the formula to find the modified surface area?
Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0

The modified area is (1/48) (2πr(4h+3r))

<u>Step-by-step explanation:</u>

Let the radius be 'r' and height be 'h'.

Area of cylinder= 2π r(h+r)

The radius is shrunk down to quarter of its original radius

 r = r/4

The height is reduced to a third of its original height

h = h/3

New Area = 2π(r/4) [(h/3) +(r/4) ]

= (1/4)2πr[(4h+3r) /12]

= (1/48) (2πr(4h+3r))

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Rewrite the quadratic function in intercept or factored form<br> y=-40x+2x^2-2x
poizon [28]

Answer:

y = 2x(x - 21)

Step-by-step explanation:

The given quadratic function y = -40x + 2x^2 - 2x

This can be rearranged as

y = 2x^2 - 2x - 40x

Here the Greatest Common Factor is 2x, we can take it out and write the remaining term in parenthesis.

y = 2x(x - 1 -20)

y = 2x(x - 21)

That's the answer.

Hope this will helpful.

Thank you.

4 0
3 years ago
58. Consider the graph of the line below. a State the slope of the line. b. State the x-intercept as an ordered pair. c. State t
mina [271]

Answer:

No solution is possible

Step-by-step explanation:

You failed to include the graph.

6 0
3 years ago
Mason will use a 1/3 gallon pitcher to fill an empty 3/4 gallon water jug. How much water will he need in order to completely fi
kirza4 [7]

Answer:

It's 1/2  I found this out by subtracting 3/4 - 1/3= 5/12 and if you put that into a decimal it would be .41. So that 1/4= .25 and 1/2= .50. You could figure out that it’s closed to 1/2.

3 0
2 years ago
Read 2 more answers
. You want to buy a book worth Php 220.50. You can buy it only by making a sacrifice of not buying a soft drink every day. If so
kherson [118]

Answer:

B-14

Step-by-step explanation:

Divide 220.50 by 15.75 and you will get 14

Hope it can help you lovelots

4 0
3 years ago
Read 2 more answers
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
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