The modified area is (1/48) (2πr(4h+3r))
<u>Step-by-step explanation:</u>
Let the radius be 'r' and height be 'h'.
Area of cylinder= 2π r(h+r)
The radius is shrunk down to quarter of its original radius
r = r/4
The height is reduced to a third of its original height
h = h/3
New Area = 2π(r/4) [(h/3) +(r/4) ]
= (1/4)2πr[(4h+3r) /12]
= (1/48) (2πr(4h+3r))
Answer:
x = 10.6 units
Step-by-step explanation:
We can use sine to solve this since sine is opposite over hypotnuse.
sin(62) = x/12
.883 = x/12
x = .883 * 12
x = 10.6
Answer:5
you do it
la respuesta es 86
C
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