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Slav-nsk [51]
3 years ago
11

The dollar value v (t) of a certain car model that is t

Mathematics
1 answer:
Yanka [14]3 years ago
7 0
Hdddddddgggggggggggggggg
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Your delivery runs took 7 hours 12 minutes on Monday,6 hours 46 minutes on Wednesday and 6 hours 53 minutes on Friday. What was
blagie [28]
7 hours + 6 hours + 6 hours
=19 hours
12 minutes + 46 minutes + 53 minutes
=111 minutes
=1 hour 51 minutes

19 hours + 1 hour and 51 minutes is 20 hours and 51 minutes. This is the total time.

Average time = total time/number of deliveries

(20 and 51/60) divided by 3
=6.95 hours
= 6 hours and 57 minutes
5 0
3 years ago
Read 2 more answers
how do you multiply binomials? Plz help! Will mark brainliest whoever answers first! Thank you for helping me, and have a good d
zepelin [54]

1. multiply the first term of each binomials together

2. multiply the out terms together.

3. multiply the inner terms together

4. multiply the last terms of each expression together

5. list the four results of FOIL in order

6. combine the like terms.

I hope this helps

6 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
What is the additive inverse of 0?
jenyasd209 [6]

Answer:

The additive inverse of 0 is 0.

3 0
3 years ago
Read 2 more answers
What polynomial must be added to 3x2 + 4x + 7 to obtain the sum of 0?
Dovator [93]

Answer:

do (3x2+4x+7)+y=0

y=-3x^2-4x-7

5 0
3 years ago
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