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Nimfa-mama [501]
3 years ago
6

Larry bought a container of tennis balls, shown below. The height of the container is 20.1 centimeters. Larry wants to find the

volume of one of these tennis balls, but he does not know the radius. Assuming that the balls fit snugly in the container, how can Larry find the radius of one of the tennis balls? A. Divide the height of the container by 3. B. Divide the height of the container by 6. C. Multiply the height of the container by 2. D. Multiply the height of the container by 3.
Mathematics
2 answers:
aalyn [17]3 years ago
5 0
It would "A" because the radius of a tennis ball is 6.86cm, so when you divide 20.1 by 3 you gey 6.8 which is about right
stealth61 [152]3 years ago
4 0

Answer: b) divide the hight of the container by 6

Step-by-step explanation:

dividing by 3 gets you the height of each tennis ball but to get the radius you'd divide by another 2...

The height / 6 = the radius of each tennis ball AKA the measurement for volume :)

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PLSSSSSSSSSSSSSSSSSSSSSSSS HELP ME!!
zzz [600]

Answer:

For the top table:

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

For the bottom table:

k = 5

[x] | 3.1 | 2.5 | 1.2 | 0.9 | 0.14 | 0.06 | 0.02 |

[y] | 15.5 | 12.5 | 6 | 4.5 | 0.7 | 0.3 | 0.1 |

3 0
3 years ago
P+q/2; use p=1, and q=-1
lana [24]

Answer:

0

Step-by-step explanation:

Plug p and q in

1+-1/2

0/2

0

If this helps please mark as brainliest

3 0
3 years ago
Read 2 more answers
What is the radius of a Ø6.75" circle? 3.375" or 3.750" or 4.375" or 6.750"
zysi [14]

Answer:4.375

Step-by-step explanation:

4 0
3 years ago
What's two thirds of a straight line?
Komok [63]
Well if the straight line is equal to 1 then your answer is 2/3 but if the straight line is not equal to 1 you need to know what it is equal to or you could use the equation y = (2/3)x
"x" would be the length of the straight line and "y" would be two-thirds of it
6 0
4 years ago
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) afte
Vlad1618 [11]

A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

The complete question is:

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is  16 feet. Round your answer(s) to the nearest hundredth.

The time at which the height of the ball is 16 feet can be found by,

h = 2 + 31t - 16t²

16 = 2 + 31t - 16t²

16 - 2 - 31t + 16t² = 0

16t² - 31t + 14 = 0

t = \dfrac{-(-31)\pm \sqrt{(-31)^2-4(16)(14)}}{2(16)}\\\\

t = 0.717 , 1.221

Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

Learn more about Quadratic Equations:

brainly.com/question/2263981

#SPJ1

4 0
2 years ago
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