So first you have to move the -2 over to the opposite side.
8(9x-4)=3+2+2
Then you can simplify the right side
8(9x-4)=7
Then you distribute
8*9x=72x
8*-4=-32
so now you have...
72x-32=7
Then you move the 37 over
72x=39
Then you divide by 72 to isolate x
x=39/72 or x= 13/24 or <span>x=0.54167</span>
It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.
<h3>How to illustrate the information?</h3>
It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.
1934 = 1000 + 900 + 30 + 4
Therefore the value of 9 will be:
= 30 × 3
Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.
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Answer:
- 34 < x < 10
Step-by-step explanation:
Inequalities of the type | x | < a, always have a solution of the form
- a < x < a
given | x + 12 | + 5 < 27 ( subtract 5 from both sides )
| x + 12 | < 22, then
- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )
- 34 < x < 10
1) (2i-4)-(6i+9) = 2i-4-6i-9 = -4i-13
2) (-3+8i)+(3-8i) = -3+8i+3-8i = 0+0i = 0