3 years ago

The student council at Oakdale High School is making T-shirts to sell for a fundraiser, at a

1 answer:

3 0

0 = 10x - 150

hopethishelps

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Pavel [41]

To find:

An irrational number that is greater than 10.

Solution:

Irritation number: It cannot be expression in the form of $\dfrac{p}{q}$ , where, $q\neq 0, p,q$ are integers.

For example: $\sqrt{2}\sqrt{3},\pi, 1.263689...,etc.$ .

We know that square of 10 is 100. So, square root of any prime number is an example of an irrational number that is greater than 10.

First prime number after 100 is 101.

Required irrational number $=\sqrt{101}$

Therefore, $\sqrt{101}$ is an irrational number that is greater than 10.

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givi [52]

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