If the perimeter is 16, the side length is 4 units.
To find the area of the shaded sections, you will use the fractional part that each section represents and multiply that fraction by the total area of the square.
Area of DEA is 1/4 of 16 square Units (4 x 4).
1/4 x 16 = 4 square units
Area of EFB is 1/8 of 16 square units.
1/8 x 16 = 2 square units
4 square units +2 square units equals 6 square units.
The area of the shaded region is 6 square units.
Answer:12
Step-by-step explanation:They are adding three box for every building so is the fifth block you do it
<span>Part
A: Solve A = (x + 23) for x.
A = x + 23
=> A - 23 = x + 23 - 23
=> A - 23 = x
=> x = A - 23 <------- answer
Part B: Determine the value of x
when A = 108
Replace the value of A in the expression x = A - 23
x = 108 - 23 = 75
x = 75 <------- answer
Part C: Solve -np - 90 > 30 for n.
-np - 90 > 30
=> -np + np - 90 >30 + np
=> - 90 > 30 + np
=> -90 - 30 > 30 - 30 + np
=> -120 > np
=> np < - 120 <----- answer
</span>
<em>Answer:</em>
<em>Can be found below</em>
<em>Step-by-step explanation:</em>
<em>Part A:</em>
<em>So we know that the bacteria doubles every (30) minutes.</em>
<em>2000 times 2 equals 4000 (30 minutes)</em>
<em>4000 times 2 equals 8000 (1 hour)</em>
<em>Answer for Part A:</em>
<em>8000 bacteria</em>
<em>Part B:</em>
<em>Now we do this function 2000(2)^14 (30 minutes long)</em>
<em>Answer to Part B: </em>
<em>I believe the answer is 32,768,000 (Please correct me if I'm wrong) </em>
<em>Hope I could help!! Have a great day/night!</em>
<em>Any constructional messages are greatly appreciated!!</em>
Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2
Step-by-step explanation:
For both : since they are asking for the area, you should calculate the perimeter.
So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.
And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.
