Answer:
The 4th graph
Step-by-step explanation:
To determine which graph corresponds to the f(x) = \sqrt{x} we will start with inserting some values for x and see what y values we will obtain and then compare it with graphs.
f(1) = \sqrt{1} = 1\\f(2) = \sqrt{2} \approx 1.41\\f(4) = \sqrt{4} = 2\\f(9) = \sqrt{9} = 3
So, we can see that the pairs (1, 1), (2, 1.41), (4, 2), (3, 9) correspond to the fourth graph.
Do not be confused with the third graph - you can see that on the third graph there are also negative y values, which cannot be the case with the f(x) =\sqrt{x}, the range of that function is [0, \infty>, so there are only positive y values for f(x) = \sqrt{x}
Answer:
noisy I think because of how they're describing them
Answer:
First option
Step-by-step explanation:
There's no value of x which makes the function undefined .
So x can take any real value
i.e. -infinity < x < +infinity
Answer:
The answer is:
Option 4; (14+ 9) 4 is twice as much as(14 + 9) 2
Thanks