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Strike441 [17]
3 years ago
10

So u all that help can see it better

Mathematics
2 answers:
KiRa [710]3 years ago
6 0
#2 the pattern is by 5 
#4 the pattern is by 7 

krek1111 [17]3 years ago
5 0
The patterns are 5, and 7
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Answer:

5.29

Step-by-step explanation:

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Please Help me this is the first part of 4 in this question. I will be posting the other 3 shortly. I need the answer. This is v
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Answer:

y = 1/6x + 5

Step-by-step explanation:

-x + 6y = 30

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y = 1/6x + 5

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Find the slope of the line through
Dafna11 [192]
When finding the slope between two points, we simply take (y2-y1) / (x2-x1)
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What is the slope of this line?
Anvisha [2.4K]
(-4,5),(0,6)

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\frac{5 - 6}{ - 4 - 0}  =   \frac{ - 1}{ - 4}  =  \frac{1}{4}
1/4
5 0
3 years ago
Two coins, A and B, each have a side for heads and a side for tails. When coin A is tossed, the probability it will land tails-s
BlackZzzverrR [31]

Answer:

Is the number of tosses for each coin enough for the sampling distribution of the difference in sample proportions PA-PB to be approximately normal?

b. No, 20 tosses for coin A is enough, but 20 tosses for coin B is not enough.

Step-by-step explanation:

a) Data and Calculations:

The probability of coin A landing tails-side up = 0.5

The proportion of times coin A lands tails-side up (PA) = 20 * 0.5 = 10

Therefore, the probability of coin A landing heads-side up = 0.5 (1 - 0.5)  

And the proportion of times that coin A lands heads-side up = 20 * 0.5 = 10.  

The proportion on either side is equally distributed.

This is why 20 tosses for coin A is enough, since the sample proportions PA is approximately normal, symmetric, and equally distributed.  There will be equal amounts of 10 tosses (0.5 *20) for either heads-side up or tails-side up.

For coin B, the probability of landing tails-side up = 0.8

The proportion of times coin B lands tails-side up (PB) = 20 * 0.8 = 16

Therefore, the probability of coin B landing heads-side up = 0.2 (1 - 0-.8)

The proportion on either side is not equally distributed, but skewed.

This is why 20 tosses for coin B is not enough, since the sample proportions PB is not approximately normal, symmetric, and equally distributed.  There will be 16 tosses landing tails-side up (0.8*20) and only 4 tosses landing heads-side up (0.2*20).

6 0
3 years ago
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