Rectangle: a = w x l
Square: a = a^2
Triangle: a= b x h divided by 2
Parallelogram: a = HH
Trapezoid: a = a+b
2h
Answer:
Yes, A KLP can be reflected across the line containing KP and then translated so that Pis mapped to M.
Step-by-step explanation:
The figure shows two congruent by HA theorem (they have congruent hypotenuses and a pair of congruent angles adjacent to the hypotenuses) triangles KLP and QNM.
A rigid transformation is a transformation which preserves lengths. Reflection, rotation and translation are rigit transformations.
If you reflect triangle KLP across the leg KP and translate it up so that point P coincides with point M , then the image of triangle KLP after these transformations will be triangle QNM.
There is the formula now just plug in the values and you will get your answer.
2/3 is the correct answer because it’s bigger then a half
