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julsineya [31]
3 years ago
11

M

Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

m∠JXM + m∠NXP = 180° - m∠MXN = 90°

You might be interested in
5. Find the 34th term in the arithmetic sequence 9, 6, 3, <br> A. 90<br> B. -90<br> C.-57<br> D. 108
mafiozo [28]

Answer:

B. -90

Step-by-step explanation:

a1=9; d=-3

a34=9-3(33-1)=-90

8 0
3 years ago
A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
Yakvenalex [24]

Answer:

The null hypothesis is, {H₀}: p = 0.66, H₀: p = 0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

Step-by-step explanation:

Let p represent the proportion of students who are supportive of making the day before Thanksgiving a holiday.

Since two populations are considered, the alternative hypothesis for the difference of the means of the two populations has to be stated.

The proportion of two-third students are supportive of making the day before Thanksgiving a holiday is p = 0.66 obtained as shown below:

The null hypothesis is,

{H₀}:p = 0.66, H₀​: p = 0.66

The alternative hypothesis is,

{Hₐ:p > 0.66, Ha​: p > 0.66

The null hypothesis is, {H₀}: p = 0.66, H₀: p=0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ​: p > 0.66

3 0
3 years ago
The school soccer team buys 3 soccer balls for every 2 players. The school volleyball team buys 7 volleyballs for every 5 player
SSSSS [86.1K]
Soccer buys more; divide each

Soccer- 3/2= 1.5
Volleyball- 7/5=1.4

Soccer buys more balls per player
6 0
3 years ago
In a study, researchers wanted to measure the effect of alcohol in the development of the hippocampal region in adolescents. The
lbvjy [14]

Answer:

Kindly check explanation

Step-by-step explanation:

Given :

Sample size, n = 30

Tcritical value = 2.045

Null hypothesis :

H0: μ = 9.08

Alternative hypothesis :

H1: μ≠ 9.08

Sample mean, m = 8.25

Samole standard deviation, s = 1.67

Test statistic : (m - μ) ÷ s/sqrt(n)

Test statistic : (8.25 - 9.08) ÷ 1.67/sqrt(30)

Test statistic : - 0.83 ÷ 0.3048988

Test statistic : - 2.722

Tstatistic = - 2.722

Decision region :

Reject Null ; if

Tstatistic < Tcritical

Tcritical : - 2.045

-2.722 < - 2.045 ; We reject the Null

Using the α - level (confidence interval) 0.05

The Pvalue for the data from Tstatistic calculator:

df = n - 1 =. 30 - 1 = 29

Pvalue = 0.0108

Reject H0 if :

Pvalue < α

0.0108 < 0.05 ; Hence, we reject the Null

4 0
2 years ago
The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no expo
Ber [7]

The option B is correct option. Thus, the Study design is used is a Case control study.

According to the statement

we have given that the incident cases of MI diagnosed in the emergency rooms of several hospitals is 500 and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases.

And we have  to find that the all these type of reports are formed which study method in medical science.

So, For this purpose, we know that the

A case control study is a  study that compares two groups of people: those with the disease or condition under study (cases) and a very similar group of people who do not have the disease or condition (controls).

This study is perfectly match with the given condition.

So,

Case-control study is used in it by the below written way:

The study design relies on hospital-based recruitment of cases (persons with an MI) and controls (other patients in the emergency room who did not have cardiovascular and respiratory diseases which may be associated with air pollution). The exposure under investigation is a time-dependent measure of exposure to high-density automobile traffic in the days preceding the emergency room visit.

So, The option B is a correct option. The Study design is used is a Case control study.

Learn more about Case control study here

brainly.com/question/24087096

Disclaimer: This question was incomplete. Please find the full content below.

Question:

The effect of exposure to high-density automobile traffic either as a bicyclist or pedestrian was compared to minimal or no exposure to automobile traffic. It is hypothesized that direct exposure to automobile traffic has an effect on acute myocardial infarction (MI). This association was studied with 500 incident cases of MI diagnosed in the emergency rooms of several hospitals and compared to 1,000 other subjects who visited the same emergency rooms for reasons other than cardiovascular and respiratory diseases. All subjects were asked to report the amount of time that they spent exposed to high-density traffic over the past month prior to their hospital visit.

What type of study design is this?

A) Cross-sectional

B) Case-control

C) Retrospective cohort

D) Prospective cohort

E) Randomized clinical trial

#SPJ4

5 0
2 years ago
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