1400kg.
Force=ma
2100N= m*1.5
2100/1.5= 1400kg.
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Answer:
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ALS OTHE ANSWEER IS A>6x+16=49>2
Step-by-step explanation:
Answer:
The maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.
Step-by-step explanation:
Given : A total of 1,000 BTUs are needed to cool a space. If 2.5 BTUs are needed to cool 1 cubic foot of space.
To find : What is the maximum volume of space that 1,000 BTUs will cool?
Solution :
Applying unitary method,
2.5 BTU are needed to cool 1 cubic foot of space.
So, 1 BTU are needed to cool cubic foot of space.
Then,1000 BTU are needed to cool cubic foot of space.
i.e. 1000 BTU are needed to cool 400 cubic foot of space.
Therefore, the maximum volume of space that 1,000 BTUs will cool is 400 cubic foot.
Answer:
Step-by-step explanation:
9) PQR Is an isosceles triangle
=> ∠PRQ = (180° - x)/2
PRS is an isosceles right triangle
=> ∠PRS = 45°
Have: ∠PRS + ∠PRQ = 115°
=>
=> 180 - x = (115 - 45).2 = 140
<=> x = 180 - 140 = 40
10) ABD is an isosceles right triangle => ∠ABD = 45°
BCD is an equilateral triangle => ∠CBD = 60°
have: x = ∠ABD + ∠CBD = 45° + 60° = 105°
11) have: x = y (2)
PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40
QTS is an isosceles triangle => ∠TQS = 180 -2x
QRS is an isosceles triangle => ∠RSQ = y
have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)
(1)(2) =>
=> x + y = 80
12) EFJ Is an equilateral triangle => ∠FJE = 60
∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle
=> 60 = 2.∠JHF => ∠JHF = 30°
∠JHF is the outer angle of the triangle FHG
=> 30° = 2x
<=> x = 15°