Answer:
All answers other than {7, 11, 15, 19}
Step-by-step explanation:
If we have a Set A, it is a subset of Set B if every element in A is also in B. Set A is a proper subset of Set B if it is a subset of Set B but not equal to Set B.
Using the above information, we know that the proper subset of {7, 11, 15, 19} cannot be itself, so we can rule out the second option.
All of the other options are sets where every element of that set is also an element of {7, 11, 15, 19}. The 3rd option is an empty set, which is a proper subset of any set other than itself, so it is a proper subset of {7, 11, 15, 19}.
Therefore, all of the options except for {7, 11, 15, 19} are valid.
Answer:
Please see the image for solution
Step-by-step explanation:
Answer: See explanation
Step-by-step explanation:
6 sacks of potatoes weigh 122.4 kg
1 sack would weigh 122.4 kg ÷ 6
122.4 ÷ 6 = 20.4
1 sack of potatoes weighs 20.4 kg
4 sacks of onions weigh 50 kg
1 sack would weigh 50 kg ÷ 4
50 ÷ 4 = 12.5
1 sack of onions weighs 12.5 kg
Answer:
x=8
Step-by-step explanation:
