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fomenos
3 years ago
5

9. Find the value of x that makes triangle FGH is congurent to triangle JKL

Mathematics
1 answer:
kotykmax [81]3 years ago
7 0
? Where is the picture of the triangle ? You need to show a picture
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Will mark brainiest!!!
romanna [79]

B

Happy to help :)

Have a great day:)

3 0
2 years ago
Find the coordinates of each point ( I, J, K) after the given transformation.
Andrews [41]

Answer:

Your answer would be I= (2,-1) J= (2,-3) and K= (5,-2)

Step-by-step explanation:

By reversing the coordinates across the x-axis, you will reverse the y coordinate (ex. 4,1 will become 4,-1). If you reverse the coordinates across the y-axis, you will reverse the x coordinate.

6 0
3 years ago
Read 2 more answers
How to show the tens fact you used. write the difference. <br> 12-7=____<br> 10-___=____
prisoha [69]
The first answer is 5,but i don't know about the second one. (sorry)
3 0
3 years ago
Helpppppppppppppppppp
makvit [3.9K]

Answer:

c. 25

Step-by-step explanation:

100/12 = 8.3

8.3 × 3 = 24.9

rounded up is 25

6 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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