Answer:
g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.
Explanation:
Sulfuric acid is represented as H₂SO₄ and calcium hydroxide is represented as Ca(OH)₂.
- To balance a chemical reaction. we should apply the law of conservation of mass that the no. of different atoms in both sides (reactants and products).
- The only choice that represent the reactants correctly and apply the law of conversation of mass is:
<em>g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.</em>
<em></em>
<em>f. H₂SO₄ + 2Ca(OH)₂ → 2CaSO₄ + 3H₂O </em>
is not correct that the no. of S, and O is not equal in both reaction sides.
S in reactants (1) while in products (2).
<em>O in reactants (8) while in products (11).</em>
<em></em>
<em>h. HSO₄ + CaOH → CaSO₄ + H₂O</em>
The reactants is represented in a wrong way.
<em> j. H₂SO₄+ Ca(OH)₂ → CaSO₄ + H₂O</em>
is not correct that the no. of H and O is not equal in both reaction sides.
H in reactants (4) while in products (2).
O in reactants (6) while in products (5).
<em></em>
<em>So, the right choice is: g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.</em>
<em></em>
Answer:
20.180
Explanation:
Atomic mass is the sum of the masses of the protons, neutrons, and electrons in an atom, or the averagemass, in a group of atoms
Answer:
Mass = 234 g
Explanation:
Given data:
Mass of NaCl produced = ?
Moles of chlorine = 2.0 mol
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
now we will compare the moles of NaCl with chlorine gas.
Cl₂ : NaCl
1 : 2
2.0 : 2/1×2.0 = 4.0 mol
Mass of NaCl;
Mass = number of moles × molar mass
Mass = 4.0 mol × 58.5 g/mol
Mass = 234 g
Answer:
79.0 mL
Explanation:
Given data
- Initial concentration (C₁): 10.0 M
- Final concentration (C₂): 1.00 M
- Final volume (V₂): 790.0 mL
In order to find the volume required of the concentrated solution, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂/C₁
V₁ = 1.00 M × 790.0 mL/10.0 M
V₁ = 79.0 mL
Protective Action Zone is the range instantly neighboring and downwind from the underlying seclusion zone; this zone is in inevitable risk of being defiled via airborne vapors inside 30 minutes of material discharge. Physically securing and keeping up the crisis scene by building up borders and defensive activity zones and denying section to unapproved people.