The equation computed shows that the numbers will be 9, 11 and 13.
<h3>How to illustrate the information?</h3>
Let the numbers be:
First number = x
Second number = x + 2,
Third number = x + 4.
Total of the numbers = 33
The equation will be:
= first + second + third number
x + x + 2 + x + 4 = 33
3x + 6 = 33
Collect like terms
3x = 33 - 6
3x = 27.
Divide both side by 3
3x/3 = 27/3
x = 9
First number = x = 9
Second number = x + 2 = 9 + 2 = 11
Third number = x + 4. = 9 + 4 = 13
The numbers will be 9, 11, and 13.
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Illustrate the equation to find three consecutive odd integers whose sum is 33.
Answer: 5.17, -0.67
Step-by-step explanation: Solve the equation for p by finding a, b, and c of the qudratic then applying the qquadratic formula
Excact Form: p = 9 + √137/4, 9 - √137/4
Decimal Form:
p = 5.17617497 . . . , -0.67617497 . . .
Hope this helps! :)
~Zane
Answer:
1 5/7
Step-by-step explanation:
-9 2/7 -(-10 3/7) recall -×- = +
-9 2/7 +10 3/7
1 2+3/7
1 5/7
<h3>
Answer: 25w+200 > 750</h3>
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Explanation:
He starts off with 200 cards. Then he adds on 25w more cards for each week (w). Overall, he'll have 200+25w cards
We can think of it like this:
- After 1 week, he adds on 25*1 = 25 cards
- After 2 weeks, he adds on 25*2 = 50 cards total
- After 3 weeks, he adds on 25*3 = 75 cards total
- After 4 weeks, he adds on 25*4 = 100 cards total, and so on.
- After w weeks, he adds on 25w cards total
So that's another way to see where the 25w comes from.
The expression 200+25w is the same as 25w+200. This is because we can add two numbers in any order.
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Since he wants to know when he'll have more than 750 cards, this means we set 25w+200 greater than 750.
That's how we get to the answer of 25w+200 > 750
Notice how there isn't a line under the inequality sign. We aren't using the "greater than or equal to" symbol here. We want to know when the cards gets over 750, but we don't want to know when it's equal to 750.
Answer:
{-1, 0,5}
Step-by-step explanation:
