Question

The height of a rocket, launched from the ground, is given by the function y = 30t - 5t^2, where y is in meters and t is in seconds. An observer is sitting at ground level a distance d from the launch point. If r is the distance between the observer and where the rocket is, show that dr/dt = ((30t - 5t^2)(30 - 10t)) / sqrt((30t - 5t^2)^2 + d^2). Show all your work.
pls help i need this by 11 pm ty :)

Answer 1

Answer:Rocket Launch A toy rocket is launched straight up in the air from level ground. The distance (in ft) the rocket is above the ground (the position function) is f (t) = 170t -16t2 at any time t (in sec) . Find

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