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Varvara68 [4.7K]
2 years ago
6

The height of a rocket, launched from the ground, is given by the function y = 30t - 5t^2, where y is in meters and t is in seco

nds. An observer is sitting at ground level a distance d from the launch point. If r is the distance between the observer and where the rocket is, show that dr/dt = ((30t - 5t^2)(30 - 10t)) / sqrt((30t - 5t^2)^2 + d^2). Show all your work.
pls help i need this by 11 pm ty :)
Mathematics
1 answer:
Alex17521 [72]2 years ago
7 0

Answer:Rocket Launch A toy rocket is launched straight up in the air from level ground. The distance (in ft) the rocket is above the ground (the position function) is <em>f (t) = 170t -16t2 at any time t (in sec) . Find </em>

Step-by-step explanation:

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Find the factors of f(x), given that x = −2 is a zero. HELP PLEASE!!
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(x+2)(x+3)(x-4)

Step-by-step explanation:

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The given factor is.

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We need to find the factors of given factor.

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f(x)=x^{3}+x^{2}-14x-24

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f(x)=x^{3}+x^{2}-4x-10x-24

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f(x)=x[(x+2)(x-2)]+(x+2)(x-12)

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f(x)=(x+2)[x^{2}-2x+x-12]

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f(x)=(x+2)(x-4)(x+3)

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