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3 years ago

HELP ASAP Use the data below

Mathematics

1 answer:

beks73 [17]3 years ago

8 0

Answer:

Part A:

-Minimum: 10

-Q1: 17.5

-Median: 30

-Q3: 42.5

-Maximum: 50

Step-by-step explanation:

Part B: IQR= 25

This shows that the data varies for 25 different numbers. That HALF of the data is between 25 numbers.

Part C: Using a box-and-whisker plot you can interpret the different values. Minimum is the first dot (10), connected to the first line (Q1 which is 17.5), connected by a box to the median (30), connected by a box to the third line (Q3 which is 42.5), connected to the last dot which is the maximum (50). And IQR is Q3-Q1, so 42.5-17.5 which is 25.

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Answer:

see explanation

Step-by-step explanation:

Given

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The height of an equilateral triangle h equals 3√2s where s is the length of a side. Suppose an equilateral triangle is made wit

nirvana33 [79]

Answer:

The correct option is;

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Step-by-step explanation:

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The sides of the equilateral triangle = Comprises multiples of 2 inches

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3 years ago

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The cost of 4 cartons of fresh cream is 5.76. What is the cost of 13 such Cartons?

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2 years ago

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Given: ∆ABC, AB = BC, BM = MC<br> AC = 40, m∠BAC = 42º<br> Find: AM

Anna [14]

Answer:

The length of AM is 26.50 units.

Step-by-step explanation:

Given information: AB = BC, BM = MC , AC = 40, ∠BAC = 42º.

Since two sides of triangle are equal, therefore the triangle ABC is an isosceles triangle.

The corresponding angles of congruents sides are always equal. So angle C is 42º.

According to the angle sum property the sum of interior angles is 180º.

$\angle B=180-42-42=96$

Law of Sine

$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$

$\frac{\sinB}{AC}=\frac{\sin(C}{AB}$

$\frac{\sin(96)}{40}=\frac{\sin(42}{AB}$

$AB\sin(96)=40\sin(42)$

$AB=\frac{40\sin(42)}{\sin(96)}$

$AB=26.91$

Therefore the length of AB and BC is 26.91.

Since M is midpoint of BC, so

$BM=\frac{BC}{2}=\frac{26.91}{2}=13.455$

Use Law of Cosine in triangle ABM to find the value of AM.

$a^2=b^2+c^2-2bc\cos A$

$AM^2=AB^2+BM^2-2(AB)(BM)\cos (B)$

$AM^2=(26.91)^2+(13.455)^2-2(26.91)(13.455)\cos (96)$

$AM=26.50$

Therefore the length of AM is 26.50 units.

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