A. 3n + 4
First Four Terms: 7, 10, 13, 16
Tenth Term: 34:
Plug in 10, 3 x 10 = 30 + 4 = 34
B. 4n - 5
First Four Terms: -1, 3, 7, 11
Tenth Term: 35
Plug in 10, 4 x 10 = 40 - 5 = 35
For the first problem, the answer is D, because every year, the graph goes down by about $4,500.
For problem two,
a. It's located in quadrant one because x and y are both positive (I've attached a graph with labeled quadrants for reference)
I'm unsure about b and c but I hope I helped with the others!
Answer:
$18,007,50
Step-by-step explanation:
First, you have to calculate the 85% of the base price that the dealer pays for the car:
base price: $18,750
$18,750*85%= $15,937.5
Second, you have to calculate the 75% of the installed options price that the dealer pays:
installed options price= $2,380
$2380*75%= $1,785
Third, you have to add the 85% of the base price plus the 75% of the installed options that the dealer has to pay and you also have to add the destination charge of $285:
$15,937.5+$1,785+$285= $18,007.5
According to this, the dealer has to pay $18,007.5 for the car with a base price of $18,750 and installed options price $2380 including a destination charge of $285.
In Graph x-axis represents number of visits and y-axis represents cost.
As graph comes up to be a linear one, so we can clearly say that cost is increasing linearly in multiples of 5.5 with increase in number of visits.
Example :
If museum is visited once then cost (y) = 5.5 x 1 = 5.5
If museum is visited twice then cost (y) = 5.5 x 2 = 11
If museum is visited thrice then cost (y) = 5.5 x 3 = 16.5
... cost (y) goes on in creasing when number of visits (x) increase with multiples of 5.5
