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3 years ago

If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars?

Mathematics

1 answer:

alukav5142 [94]3 years ago

5 0

Answer:

2/9 boxes.

Step-by-step explanation:

6 / 1 / 3 = 4 / b

Cross multiply the two

6b = 4/3

Multiply 1/6 on each side

B = 4 /18

It can be reduced to 2/9.

Feel free to let me know if you need more help! :)

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Four expressions equivalent to 4(3/5)

kondaur [170]

1. 12/5
2. 24/10
3. 48/20
4. 96/40

5 0

3 years ago

Read 2 more answers

Roberta makes $9 an hour plus a 10.5% commission selling jewelry an hour shift in which she sells $880 worth of jewelry. How muc

timama [110]

Answer:

Roberta earns $164.4 on an 8 hr shift.

Step-by-step explanation:

In one hour Roberta makes $9

So if she works for 8 hours she will be making

=> ( 9 X 8)$

=>72$

Also she earns a commission of 10.5% on selling a jewellery worth $880

So 10.5% of 880 is

=> $\frac{10.5}{100}\times 880$

=> $0.105\times 880$

=> 92.4

Hence Roberta will be earning a total amount of

(72+ 92.4)

=>$164.4

3 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

beks73 [17]

Answer:

(5.4582 ; 6.8618)

Step-by-step explanation:

Given the data:

6 10 2 6 3 3 3 6 6 6 6 5 8 9 10 10 7 9 3 6 5 10 9 9 10 3 8 6 6 3 3 6 6 5 4 10 9 3 5 7 10 6 3 8 6 8 3 3 5 5

Sample mean, xbar = Σx / n

n = sample size = 50

ΣX = 308

xbar = 308 / 50 = 6.16

Using a Calculator :

The sample standard deviation, s = 2.469

Confidence interval = xbar ± margin of error

Margin of Error = Tcritical * s/sqrt(n)

Tcritical at 95% ; df = 50 - 1 = 49

Tcritical = 2.010

Hence,

Margin of Error= 2.010 * (2.469/sqrt(50)) = 0.7018

Lower boundary : (6.16 - 0.7018) = 5.4582

Upper boundary : (6.16 + 0.7018) = 6.8618

(5.4582 ; 6.8618)

4 0

3 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

3 years ago

So I have to compute the following but i don't know what they mean any help?

Gelneren [198K]

Answer:

Step-by-step explanation:

This is a Combination (as in permutation vs combination) question the symbol (n r) refers to "n choose r". This is sometimes written as nCr

i.e the question is asking you to find how many combinations each will yield when you chose r items from n item without repetition and order does not matter.

I will only do the first question for you and you can just follow the same steps to solve the rest of the questions.

Recall that

$nCr=\frac{n!}{(r!)(n-r)!}$

Consider question a) we are given (5 1) or ₅C₁

we can see that n = 5 and r = 1

If we substitute this into the formula:

₅C₁ = (5!) / [ (1!)(5- 1)!]

= (5!) / [ (5- 1)!]

= (5!) / (4!)

= (5·4·3·2·1) / (4·3·2·1)

= 5

hence ₅C₁ = 5

7 0

3 years ago

Read 2 more answers