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fgiga [73]
3 years ago
5

What is the least common multiple of 12 and 7?

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

84

Least common multiple (LCM) of 7 and 12 is 84.

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1. Suzette ran and biked for a total of 60 mi in 6 h. Her average running speed was 4 mph and her average biking speed was 12 mp
evablogger [386]

Suzette ran for 1.5 hours and biked for 4.5 hours

Step-by-step explanation:

The given is:

  • Suzette ran and biked for a total of 60 miles in 6 hours
  • Her average running speed was 4 mph
  • Her average biking speed was 12 mph
  • Let x = total hours Suzette ran
  • Let y = total hours Suzette biked

∵ x represents the total hours Suzette ran

∵ y represents the total hours Suzette biked

∵ Suzette ran and biked for a total 6 hours

∴ x + y = 6 ⇒ (1)

∵ Her average running speed was 4 mph

∵ Her average biking speed was 12 mph

∵ Distance = speed × time

∴ Her total distance = 4 x + 12 y

∵ Suzette ran and biked for a total of 60 miles

- Equate the two expressions of her total distance

∴ 4 x + 12 y = 60 ⇒ (2)

Now let us solve the system of equations to find the values of x and y

Multiply equation (1) by -4 to eliminate x

∵ (-4) x + (-4) y = (-4)(6)

∴ -4 x - 4 y = -24 ⇒ (3)

- Add equations (2) and (3)

∴ 8 y = 36

- Divide both sides by 8

∴ y = 4.5

∴ Suzette biked for 4.5 hours

- Substitute the value of y in equation (1) to find the value of x

∵ x + 4.5 = 6

- Subtract 4.5 from both sides

∴ x = 1.5

∴ Suzette ran for 1.5 hours

Suzette ran for 1.5 hours and biked for 4.5 hours

Learn more:

You can learn more about system of equations in brainly.com/question/6075514

#LearnwithBrainly

8 0
3 years ago
Determine the t critical value for a lower or an upper confidence bound in each of the following situations. (Round your answers
Vinvika [58]

Answer:

A. 1.812

B. 1.753

C. 2.602

D. 3.747

E. 2.069

F. 2.453

Step-by-step explanation:

A. 95% confidence level, the level of significance = 5% or 0.05

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 10 degrees of freedom = 1.182

B. 95% confidence interval = 0.05 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.05 significance level with 15 degrees of freedom = 1.753

C. 99% confidence interval = 0.01 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 15 degrees of freedom = 2.602

D. 99% confidence interval = 0.01 level of significance; DF (n - 1) = 5- 1 = 4

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 4 degrees of freedom = 3.747

E. 98% confidence interval = 0.02 level of significance

Using t-table, the critical value for a lower or an upper confidence bound at 0.02 significance level with 23 degrees of freedom = 2.069

F. 99% confidence interval = 0.01 level of significance; df (n - 1) = 32 - 1 = 31

Using t-table, the critical value for a lower or an upper confidence bound at 0.01 significance level with 31 degrees of freedom = 2.453

7 0
4 years ago
Subtract. Write the answer in standard form.<br><br> (12+4i)−(3−7i)
labwork [276]

Answer:

9+11i

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
Write the number in i-form.<br><br> −4
kodGreya [7K]

Answer:

\huge\boxed{\sf 4i^2}

Step-by-step explanation:

\sf = -4\\\\We \ know \ that\ i^2 = -1 \\\\= 4 (-1)\\\\= 4i^2\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
10. EQAO Sam works in Peterborough. Each
Svet_ta [14]
Answer is A, 10.4L per 100km
4 0
3 years ago
Read 2 more answers
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