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3 years ago

Use the two patterns below

1 answer:

5 0

Let's say u put those 2 patterns onto a graph it would be (x,y) (3,5). same for the next (6,10). I'm sorry if this didn't help I'm trying though

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10 squared take away four cubed

Tems11 [23]

10 squared = 100
4 cubed = 16
100-16 =84

7 0

3 years ago

He collected a total of 225 . If 68% of the stamps he collected were foreign, how many other stamps did he collect?

MissTica

Answer:

72 stamps

Step-by-step explanation:

First, we're looking to find the number of stamps that AREN'T foreign, so we have to subtract 68% from 100%.

100% - 68%
32%

Now, we know that 32% of the stamps are NOT foreign. So, next, we:

Multiply 32 by 225.
Divide the product of 32 and 225 by 100

$32*225$
$7200$
$7200/100$
$72$

Therefore, the answer is 72 stamps.

4 0

2 years ago

In a certain city with a working population of 10,500 , 8925 people and less than $75,000 per year what is a percentile rank of

zysi [14]

Answer:

The percentile rank of someone who earns $75,000 per year is the 85th percentile.

Step-by-step explanation:

Meaning of percentile:

When a value V is said to be in the xth percentile of a set, x% of the values in the set are lower than V and (100-x)% of the values in the set are higher than V.

In this question:

Working population of 10,500

8,925 people earn less than $75,000 per year.

8925/10500 = 0.85

0.85*100 = 85

The percentile rank of someone who earns $75,000 per year is the 85th percentile.

4 0

3 years ago

How do we solve this I need a quick answer please :)

andre [41]

Sorry don't no the answer

sorry if I kwon the answer

I telling u the answer

5 0

2 years ago

Read 2 more answers

In 2015, the population of a district was 10,600. With an annual growth rate of approximately 4%, what will the population be in

Murljashka [212]

Answer:

$19,090\ people$

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

$y=a(1+r)^x$

where

y is the population

x is the time in years since year 2015

a is the initial value

r is the rate of change

we have

$a=10,600\\r=4\%=4/100=0.04$

substitute

$y=10,600(1+0.04)^x$

$y=10,600(1.04)^x$

In the year 2040 the value of x is equal to

$x=2040-2015=25\ years$

substitute

$y=10,600(1.04)^{15} =19,090\ people$

7 0

3 years ago