3 years ago

In the right triangle shown, m\angle D = 60\degreem∠D=60°m, angle, D, equals, 60, degree and EF= 4\sqrt{3}EF=4

Mathematics

2 answers:

Leona [35]3 years ago

4 0

Answer: the answer is 4

Step-by-step explanation:

Svetlanka [38]3 years ago

3 0

Answer:

Step-by-step explanation:

trust me i did this khan problem

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N76 [4]

The answer is D.10 at least

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Solve 10(1 + 3b) = −20, justifying each step with an algebraic property.

Delicious77 [7]

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Hope this helps :)

4 0

3 years ago

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

4 years ago