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Alja [10]
3 years ago
12

In 2015, the population of a district was 10,600. With an annual growth rate of approximately 4%, what will the population be in

2040 according to the exponential growth function
Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

19,090\ people

Step-by-step explanation:

we know that

The equation of a exponential growth function is given by

y=a(1+r)^x

where

y is the population

x is the time in years since year 2015

a is the initial value

r is the rate of change

we have

a=10,600\\r=4\%=4/100=0.04

substitute

y=10,600(1+0.04)^x

y=10,600(1.04)^x

In the year 2040 the value of x is equal to

x=2040-2015=25\ years

substitute

y=10,600(1.04)^{15} =19,090\ people

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16 mph is the answer I found after doing the work

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3 years ago
O points
astraxan [27]

7.5 %

Step-by-step explanation:

We by finding how far from the mean the 999 volume caps are, using z score;

Z = (x – μ) / σ

Z = (999 – 998) / 7

Z = 0.143    

We use the z-table to find the confidence levels;

= 85%

= 0.85

Since we are finding proportion of bottles have volumes greater than 999

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1 – .85 = .15

0.15/2 = 0.075

= 7.5%

5 0
3 years ago
What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
2 years ago
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tigry1 [53]
5 x 2000 = 10,000 + 5 = 10,005
4 0
2 years ago
Convert ln x = y to exponential form.
LuckyWell [14K]
Answer: e^y=x

ln(x)=y

e^ln(x)=e^y

x=e^y

8 0
3 years ago
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