PLEASEEEE HELLPPPPPpppp

Can you help me please

alexira [117]

Answer:

Please check the explanation.

Step-by-step explanation:

Given that

|v|=38

Ф = 120°

<u>Finding the horizontal component</u>

The horizontal component can be obtained using the formula

Vx = |v| cos Ф

= 38 cos 120°

= 38 (-0.5)

= -19

Thus, the horizontal component is:

Vx = -19

<u>Finding the vertical component</u>

The vertical component can be obtained using the formula

Vy = |v| sin Ф

= 38 sin 120°

= 38 (0.86)

= 32.68

Thus, the vertical component is:

Vy = -19

A vector 'v' with magnitude |v| and direction Ф can be written as:

v = |v| cos Ф i + |v| sin Ф j

As

|v|=38

Ф = 120°

Thus, the vector is

v = 38 cos 120° i + 38 sin 120° j

or

v = -19 i + 32.68 j

5 0

2 years ago

A candidate took a phone poll of 110 people. Of the 110 people polled, 87 said they would vote for the other person. There are 9

SSSSS [86.1K]

Option B

7569 number of people are going to vote for the other candidate

<em><u>Solution:</u></em>

Given that candidate took a phone poll of 110 people

Of the 110 people polled, 87 said they would vote for the other person

There are 9570 people in the district

You can set up this problem like a proportion

Let "x" be the number of people who would vote for the other candidate

$\frac{87}{110} = \frac{x}{9570}$

To solve proportions, you cross-multiply. This means you multiply the numerator by the other denominator, and the denominator by the other numerator

$87 \times 9570 = 110 \times x$

832590 = 110x

x = 7569

Thus 7569 number of people are going to vote for the other candidate

6 0

3 years ago

Read 2 more answers

Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening

Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0

2 years ago

Kai is buying boxes of cookies at a bakery. Each box of cookies costs \$4$4dollar sign, 4. He wrote this equation to find how ma

IRISSAK [1]

Answer:

WHAT COLLIG U GO 2 :3

Step-by-step explanation:

CRISSY WAKE UP I DONT LIKE THIS CRISSY WAKE UP HEY HELLO TIME TO WAKE UP TIME TO WAKE UP CAN YOU HEAR ME WAKE UP CRISSY I DONT LIKE THIS CRISSY WAKE UP AHHH DIDNT MEAN TO SCARE YOUY YOU OKAY JUST GIVE ME THE WORD AND ILL JUST WALK AWAY DO YOU EVER FELL LIKE YOUR LOSING OYUR MINE ON A DAILY BASIS ALL THE THIME YOU KNOW YOUR NOT WHAT I THOUGHT YOUD BE EDDUE DID YOU FIND ANYTHING PECSIUL BLISS JUST MOMENTS AWAY CRISSY CRISSY CRISSY CRISY SWAKE UO I DONT OIKE THIS

8 0

1 year ago

Construct a 99% confidence interval to estimate the population proportion with a sample proportion equal to 0.36 and a sample s

vivado [14]

Using the z-distribution, the 99% confidence interval to estimate the population proportion is: (0.2364, 0.4836).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 99% confidence level, hence $\alpha = 0.99$ , z is the value of Z that has a p-value of $\frac{1+0.99}{2} = 0.995$ , so the critical value is z = 2.575.