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brilliants [131]
3 years ago
15

Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r

ate of increase or decrease.
y=490(0.92)^x
Mathematics
1 answer:
GREYUIT [131]3 years ago
7 0

Answer:

  • Decay
  • Decrease rate is 8%

Step-by-step explanation:

<u>Given function:</u>

  • y = 490(0.92)^x

The base of the exponent is 0.92. This represents a decay as 0.92 is less than 1. It would be a growth function is the base was greater than 1.

<u>The rate of decrease is </u>

  • 0.92 times

<u>Percent decrease is </u>

  • (1 - 0.92)*100% = 8%
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HELP............................................................................................................................
weqwewe [10]

Answer:

More than half I think its based off of a 1-10% scale

Step-by-step explanation:

it's greater than 5%

7 0
2 years ago
Simplify 14a over 15 Plus 2a + 36 over 5​
Yuliya22 [10]

Answer:

(20a+108)/15

Step-by-step explanation:

First find LCM of the denominators. U will find it to be 15

Then calculate the number like this.

[(14a)×1/15×1]+[(2a+36)×3/5]

[(14a/15)]+[(6a+108)/15

(14a+6a+108)/15

(20a+108)/15

5 0
2 years ago
Kari drew two parallel lines PQ and RS intersected by a transversal KL, as shown below:
Arlecino [84]
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK 
3 0
3 years ago
Read 2 more answers
A liquid at temperature 7575F is placed in an oven at temperature 450450. The temperature of the liquid increases at a rate 77 t
hichkok12 [17]

Answer: \dfrac{dT(t)}{dt}=77\times (450-T)

Step-by-step explanation:

Given

The temperature of the liquid is 75^{\circ}F placed in an oven with temperature of 450^{\circ}F.

Initially difference in temperature of the two

\Delta T=450-75\\\Rightarrow \Delta T=375^{\circ}F

According to the question

\Rightarrow \dfrac{dT(t)}{dt}=77\cdot \Delta T\\\\\Rightarrow \dfrac{dT(t)}{dt}=77\times (450-T)\quad [\text{T=75}^{\circ}F\ \text{at t=0}]

5 0
2 years ago
6-1/3x=-1 How do I do this
I am Lyosha [343]
Im gonna assume you mean 6 - (1/3)x = -1.  Your notation is not super clear.  If so, solution is as follows:

6 - (1/3)x = -1   [subtract 6 from both sides]
-(1/3)x = -7       [multiply both sides by -3]
x = 21

7 0
3 years ago
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