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3 years ago

Need help please and thank you

Mathematics

1 answer:

vekshin13 years ago

8 0

We can drop the absolute value and the signs, and the integer part if they're all the same, and then make a common denominator and check for a decreasing sequence.

10/12, 7/12, 5/12 -- Check decreasing

3 1/3, 3 2/3, 2 2/3 -- nope, increases then decreases

6 5/7, 6 3/7, 5 2/7 - Check, decreasing

11 7/10, 11 6/10, 10 3/10 -- Check, decreasing

Answer: A,C,D

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If 9/a = 7/a², then a=?

Jobisdone [24]

Answer:

x = 7/9

Step-by-step explanation:

5 0

3 years ago

Here are five number cards . 2,5,7,8,9 . One of the cards is removed and the mean average of the remaining four number cards is

Elodia [21]

Answer:

Step-by-step explanation:

Given that there are 5 number cards.

They are 2,5,7,8,9

Total of all numbers in the cards = 2+5+7+8+9= 31

One card is removed say with number x.

Now sum new would be =31-x .. i

Average of remaining 4 cards = 6

So sum of remaining 4 cards = 6(4) = 24 ... ii

i and ii represent the sum of remaining 4 cards. Hence they should be equal

31-x =24

Subtract 31 from both sides to get

-x=-7

Or x =7

7 0

4 years ago

Find the length of a square whose area is 0.0084m

TiliK225 [7]

Answer:

.091651514m

Step-by-step explanation:

The area of a square is found by

A = s^2 where s is the side length

.0084 = s^2

Take the square root of each side

$\sqrt{.0084} = \sqrt{s^2}$

.091651514 = s

4 0

2 years ago

Read 2 more answers

X+2=0 help thanks this is hard

djyliett [7]

-2+2=0

I hope I helped

8 0

3 years ago

Read 2 more answers

Which ordered pair is the y intercept of y=2x^2+3x-3?

rosijanka [135]

Answer:

I think it's A - (0,-3)

Step-by-step explanation:

x,y

(0,-3)

y-intercept equation for this problem:

$y=2x^{2}+3x-3$

Break it down to smaller parts:

$2(0)^{2} +3(0) = 0$

$0 - 3 = -3$

Rewriting it in a neater way:

=> $y = 2(0)^{2} +3(0) -3\\y=-3$

Therefore, answer A / the first choice is correct

- have a great day, be safe & healthy -

8 0

3 years ago

Need help please and thank you​

Need help please and thank you