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Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
is the sample proportion.
- z is the critical value.
- n is the sample size.
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:
Hence the bounds of the interval are found as follows:
The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Given:
To find:
The product of the polynomials.
Solution:
1.
Multiply the numerical coefficient and add the powers of x.
2.
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
3.
Multiply each term of first polynomial with each term of 2nd polynomial.
Multiply the numerical coefficient and add the powers of x.
Add or subtract like terms together.
The answer for multiplying polynomials: