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4 years ago

6

Help please not sure where to start

1 answer:

IrinaVladis [17]4 years ago

6 0

The answer to number one is 276

Step 1: subtract

156 - 18 = 138

Step 2: multiply

138 x 2 = 276

Step 3: Your Answer

276

Bill has 145 air planes

Dave has 145 air planes

Jack has 138 air planes

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Simply (2/5)(-5)(-4/6)

V125BC [204]

First, you multiply 2/5 by -5 to get -2. Then, you multiply -2 by -2/3 (-4/6's simplified form) to get 1 1/3 as your answer.

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3 years ago

Can someone pls help me with this?

Hatshy [7]

Answer:

Between 1 and 3 seconds

Step-by-step explanation:

There is no change in distance ( change in y ) between 1 and 3, so she wasn't walking during that time

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3 years ago

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I will give brainliest!! THERE IS NO OTHER INFORMATION GIVEN!! In ⊙O, chord XY is 8 cm long and is 10 cm from O. What is the rad

Zielflug [23.3K]

Answer:

radius ≈ 10.77 cm

Step-by-step explanation:

The segment from the centre O to the chord is a perpendicular bisector.

Thus 2 right triangles are formed with legs 10 cm and 4 cm ( half of XY )

The radius r is the hypotenuse.

Using Pythagoras' identity, then

r² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

r = $\sqrt{116}$ ≈ 10.77 cm ( to 2 dec. places )

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3 years ago

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Hey yall i would really appreciate your help on this plz

Katarina [22]

Answer:

the length of the opposite side (x), is 27.2

Step-by-step explanation:

For the given right triangle problem;

the opposite side of the given angle, opp. = 22

the hypothenuse side, hypo. = x

given angle of the triangle, θ = 54⁰

The length of the opposite side (x), is calculated as follows;

$sin \ \theta = \frac{opp.}{hypo.} \\\\sin (54) = \frac{22}{x} \\\\x = \frac{22}{sin(54)} \\\\x = 27.2$

Therefore, the length of the opposite side (x), is 27.2

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3 years ago

If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),

nikklg [1K]

Step-by-step explanation:

<u>Step 1: Solve using the first point</u>

<em>(2, 28)</em>

$28 = a(2)^3 + b(2)^2 + c(2) + d$

$28 = 8a + 4b + 2c + d$

<u>Step 2: Solve using the second point</u>

<em>(-1, -5)</em>

$-5 = a(-1)^3 + b(-1)^2 + c(-1) + d$

$-5 = -a + b - c + d$

<u>Step 3: Solve using the third point</u>

<em>(4, 220)</em>

$220 = a(4)^3 + b(4)^2 + c(4) + d$

$220 = 64a + 16b + 4c + d$

<u>Step 4: Solve using the fourth point</u>

<em>(-2, -20)</em>

$-20 = a(-2)^3 + b(-2)^2 + c(-2) + d$

$-20 = -8a + 4b - 2c + d$

<u>Step 5: Combine the first and fourth equations</u>

<u /> $28 - 20 = 8a - 8a + 4b + 4b + 2c - 2c + d + d$

$8 = 8b + 2d$

$8 - 8b = 8b - 8b + 2d$

$(8 -8b)/2 = 2d/2$

$4 - 4b = d$

<u>Step 6: Solve for c in the second equation</u>

$-5 + 5 = -a + b - c + d + 5$

$0 + c = -a + b - c + c + d + 5$

$c = -a + b + d + 5$

<u>Step 7: Substitute d with the stuff we got in step 5</u>

$c = -a + b + (4 - 4b) + 5$

$c = -a + b + 4 - 4b + 5$

$c = -a - 3b + 9$

<u>Step 8: Substitute d and c into the first equation</u>

<u /> $28 = 8a + 4b + 2(-a - 3b + 9) + (4 - 4b)$

$28 = 8a + 4b - 2a - 6b + 18 + 4 - 4b$

$28 - 22 = 6a - 6b + 22 - 22$

$6 / 6 = (6a - 6b) / 6$

$1 + b = a - b + b$

$1 + b = a$

<u>Step 9: Substitute a, b, and c into the third equation</u>

$220 = 64(1 + b) + 16b + 4(-(1 + b) - 3b + 9) + (4 - 4b)$

$220 = 64 + 64b + 16b + 4(-1 - b - 3b + 9) + 4 - 4b$

$220 - 100 = 60b + 100 - 100$

$120 / 60 = 60b / 60$

$2 = b$

<u>Step 10: Find a using b = 2</u>

$a = b + 1$

$a = (2) + 1$

$a = 3$

<u>Step 11: Find c using a = 3 and b = 2</u>

$c = -a - 3b + 9$

$c = -(3) - 3(2) + 9$

$c = -3 - 6 + 9$

$c = 0$

<u>Step 12: Find d using b = 2</u>

$d = 4 - 4b$

$d = 4 - 4(2)$

$d = 4 - 8$

$d = -4$

Answer: $a = 3, b = 2, c = 0,d = -4$

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3 years ago

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