What are the first sixty numbers of pi?

Mathematics

2 answers:

jonny [76]3 years ago

5 0

3.141592635897932384626433832279502884197169399375105820974944

There.

makkiz [27]3 years ago

5 0

The first 60 numbers of Pi are -

3.141592653589793238462643383279502884197169399375105820974944

Hope this helps! :D

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What does 6×3+(9-3)+1 equal?

Lelu [443]

Hi

6*3 + (9-3)
= 18 + 3
= 21

I hope that's help !

3 0

3 years ago

Read 2 more answers

Consider the force field and circle defined below.

grin007 [14]

By Green's theorem,

$\displaystyle\int_{x^2+y^2=9}\vec F(x,y)\cdot\mathrm d\vec r=\iint_D\left(\frac{\partial(xy)}{\partial x}-\frac{\partial(x^2)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=\iint_Dy\,\mathrm dx\,\mathrm dy$

where $C$ is the circle $x^2+y^2=9$ and $D$ is the interior of $C$ , or the disk $x^2+y^2\le1$ .

Convert to polar coordinates, taking

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\end{cases}\implies\mathrm dx\,\mathrm dy=r\,\mathrm dr\,\mathrm d\theta$

Then the work done by $\vec F$ on the particle is

$\displaystyle\iint_Dy\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^3(r\sin\theta)r\,\mathrm dr\,\mathrm d\theta=\left(\int_0^{2\pi}\sin\theta\,\mathrm d\theta\right)\left(\int_0^3r^2\,\mathrm dr\right)=\boxed0$