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3 years ago

Verify the identity. Justify each step.

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

From the trigonometry:

tan θ = (sin θ) / (cos θ)
cot θ = (cos θ) / (sin θ)

∴ tan θ + cot θ = (sin θ) / (cos θ) + (cos θ) / (sin θ)
= [ sin² θ + cos² θ]/( sin θ cos θ) = 1 /( sin θ cos θ )

note : sin² θ + cos² θ = 1

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Julli [10]

Answer:

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2 years ago

Help please?

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

3 years ago

Three consecutive integers have a sum of 42 . Find the integers.

Masteriza [31]

The three consecutive integers are13 14 and 15.

3 0

3 years ago

Give the equation of the line perpendicular to y +7= -2(x - 6) through the<br> point (6,-3)

lilavasa [31]

<u>Note: this answer assumes the equation of the line can be put in slope-intercept form. </u>

Answer:

$y + 3 = \frac{1}{2}(x-6)$

Step-by-step explanation:

1) First, find the slope of y + 7 = -2 (x - 6). We can see that it's already in point-slope form, or $y-y_1 = m (x-x_1)$ format. Remember that the number in place of the $m$ is the slope. Therefore, -2 is the slope of that equation.

What we need is the slope that is perpendicular to that, though. So, find the opposite reciprocal of -2. To do this, change its sign, convert it into a fraction ( $-\frac{2}{1}$ ), and flip its numerators and denominators. Therefore, the perpendicular slope would be $\frac{1}{2}$ .

2) Now that we have a slope and a point the line passes through, we can write an equation using the point-slope formula, $y-y_1 = m (x-x_1)$ . In order to write an equation, the $x_1$ , $y_1$ , and $m$ have to be substitute for with real values.

The $m$ represents the slope. We already calculated that in the last step, so put $\frac{1}{2}$ in place of the $m$ . The $x_1$ and $y_1$ represent the x and y values of a point the line passes through. We know that the line has to pass through (6, -3), so substitute 6 for $x_1$ and -3 for $y_1$ :

$y - (-3) = \frac{1}{2}(x -(6))\\y + 3 = \frac{1}{2}(x - 6)$

Therefore, (again, assuming that the line can be put in point-slope form) the answer is $y + 3 = \frac{1}{2}(x-6)$ .

5 0

3 years ago

Helena has saved $595 to put toward snowboarding equipment and lift tickets at the hill. Each lift ticket costs $35. If she want

Akimi4 [234]

595 - 35t > 420
-35t > 420 - 595
-35t > -175
t < 5........so she can buy 4 tickets

5 0

3 years ago