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aksik [14]
3 years ago
15

And why is it a function

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
8 0
It's not a function because the x value 2 has two y values
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Write the polynomial function with the given zeros.<br> 5. x= -1,-1, 6
Allushta [10]

Answer:

Step-by-step explanation:

There are many such polynomials, but the one with leading coefficient of 1 is

y = (x+1)(x-1)(x-6) = x^3 - 6x^2 - x + 6

Not sure what you want to do with the 5, If that is the y-intercept, then since

(1)(-1)(-6) = 6, we will need

y = 5/6 (x^3 - 6x^2 - x + 6)

5 0
3 years ago
Compare the two groups of data. Which statement is true?
kati45 [8]
D
Udisirnsornxkskrncskjt
8 0
2 years ago
What equation represents the model shown below?
g100num [7]

Given:

The algebra tiles of an equation.

To find:

The equation represented by the given model.

Solution:

On the left side of the model we have 4 tiles of (-x) and 3 tiles of (-1). So,

LHS=(-x)+(-x)+(-x)+(-x)+(-1)+(-1)+(-1)

LHS=-4x+(-3)

LHS=-4x-3

On the right side of the model we have 8 tiles of (-1). So,

RHS=(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)+(-1)

RHS=-8

Now, equate the LHS and RHS to get the equation.

-4x-3=-8

Therefore, the equation for the given model is -4x-3=-8.

7 0
2 years ago
If the mean of a given data set is 56 and the standard deviation is 10
aleksley [76]

Answer:

5.6 divided by  10

  =5.6

Step-by-step explanation:

5 0
3 years ago
When you forget to add the attachment,, r.i.p. ,, what I said before and all that
kati45 [8]
a.
h = 2c - 3

b.
3h + 1.5c = 201

c.
We have a system of equations from part a and b.
h = 2c - 3   (equation 1)
3h + 1.5c = 201   (equation 2)

We use substitution method to solve this system.
Substitute equation 1 in equation 2 to get
3h + 1.5c = 201
>> 3(2c - 3) + 1.5c = 201
>> 6c - 9 + 1.5c = 201
>> 7.5c = 201 + 9
>> 7.5c = 210
>> c = 210 / 7.5
>> c = 28

Plug this value back in equation 1 to get
h = 2c - 3  
>> h = 2(28) - 3 = 56 - 3 = 53

So, c = 28 and h = 53 implies that <u>28 corndogs</u> and 53 hotdogs were sold.
3 0
3 years ago
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