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Ipatiy [6.2K]
3 years ago
15

30 POINTS! Please answer and show work for both!

Mathematics
1 answer:
monitta3 years ago
6 0

The recommended approach for such equations is to eliminate fractions first, by multiplying by the LCM of the denominators. You can simply simplify, then work them as a 2-step linear equation, doing your arithmetic with the fractions as they are.

a) (5x-1)/7 + (4x-3)/2 -(3-2x)/2 = 6 . . . . . given

... 2(5x -1) +7(4x -3) -7(3 -2x) = 84 . . . . . multiply by 14

... 10x -2 +28x -21 -21 +14x = 84 . . . . . . eliminate parentheses

... 52x -44 = 84 . . . . . . . . . . . . . . . . . . . . collect terms

... 52x = 128 . . . . . . . . . . . . . . . . . . . . . . . add 44

... x = 32/13 . . . . . . . . . . . . . . . . . . . . . . . . divide by 52 and simplify

b) (4x−3)/2 − (5−2x)/3 − (3x−4)/3 = 5 . . . given

... 2x -3/2 -5/3 +(2/3)x -x +4/3 = 5 . . . . . . .eliminate parentheses

... (5/3)x -11/6 = 5 . . . . . . . . . . . . . . . . . . . . simplify

... (5/3)x = 41/6 . . . . . . . . . . . . . . . . . . . . . . add 11/6

... x = (41/6)/(5/3) = 41/10 . . . . . . . . . . . . . .divide by the coefficient of x

_____

Using the first method, you're dealing with integers and you can do a lot of the math in your head. Using the second method, you're dealing with fractions and mixed numbers. A calculator can be helpful, especially if it handles arithmetic with fractions nicely, as many graphing calculators do.

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ZanzabumX [31]

Rewrite it in the form a^2 - b^2, where a = 5x and b = 8

(5x)^2 - 8^2

Use the Difference of Squares; a^2 - b^2 = (a + b)(a - b)

<u>= C. (5x - 8)(5x + 8)</u>

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3 years ago
Which of the following would be equivalent to 11 to the 8th power over 11 to the 3rd power
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Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9. Wit
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There are 90 different identification numbers possible.

<h3>What are the permutation and combination?</h3>

In terms of mathematical concepts, “permutation” and “combination” are related to each other.

The combination is the counting of selections that we make from n objects.

Oscar was not safeguarding his personal identification and chose a two-digit PIN for his debit card using the numbers 0 - 9.

There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are;

10 × 10 = 100 total possible PINs.

Now, because you can't use the same number twice, we subtract 10 from 100 because there are 10 numbers that can match themselves.

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Hence, there are 90 different identification numbers possible.

Learn more about combination here;

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Option A is correct

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