Molarity = number of moles / volume
Volume = number of moles / molarity
= 25/3
= 8.3333 L
Explanation:
Any orbital can hold a maximum of 2 electrons with opposite spin. The first shell has one 1s orbital and holds 2 electrons. The second shell holds 8 electrons; 2 in a 2s orbital and 6 in three 2p orbitals. The third shell holds 18 electrons; 2 in a 3s orbital; 6 in three 3p orbitals; and 10 in five 3d orbitals.
Answer:
40.72g of sulfuric acid are needed
Explanation:
When sulfuric acid, H₂SO₄, is neutralized by lead (IV) hydroxide, Pb(OH)₄, Lead (IV) sulfate, Pb(SO₄)₂ and water as follows:
2 H₂SO₄ + Pb(OH)₄ → Pb(SO₄)₂ + 4H₂O
To solve this question we must find the moles of 57.18g of Pb(SO₄)₂. As 2 moles of H₂SO₄ produce 1mol Pb(SO₄)₂ we can find the moles of H₂SO₄ and its mass as follows:
<em>Moles Pb(SO₄)₂ -Molar mass: 275.23 g/mol-</em>
57.18g * (1mol / 275.23g) = 0.2078 moles Pb(SO₄)₂
<em>Moles H₂SO₄:</em>
0.2078 moles Pb(SO₄)₂ * (2mol H₂SO₄ / 1mol Pb(SO₄)₂) = 0.4155 moles H₂SO₄
<em>Mass H₂SO₄ -Molar mass: 98g/mol-</em>
0.4155 moles H₂SO₄ * (98g / mol) =
<h3>40.72g of sulfuric acid are needed</h3>
Answer:
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hope it helps