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Semenov [28]
4 years ago
15

what pressure, in atmospheres is exerted by 0.325 mol of hydrogen gas in a 14.08L container at 35°C ?

Chemistry
2 answers:
givi [52]4 years ago
7 0

Answer:

P=0.583atm

Explanation:

Hello,

In this case, by using the ideal gas equation:

PV=nRT

We can compute the pressure as shown below, considering the given data and absolute temperature:

P=\frac{nRT}{V}=\frac{0.325mol*0.082\frac{atm*L}{mol*K}*(35+273)K}{14.08L}\\  \\P=0.583atm

Best regards.

Setler [38]4 years ago
5 0

Answer:0.58 atm

Explanation:see attached photo

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3 years ago
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6 0
4 years ago
If the inital pressure of an ideal gas at a temperature of 344 K is 0.917 atm, what is the pressure of the gas at 322 K?
Gennadij [26K]

Answer:  P2 = 0.858 atm

Explanation:

Use the combined gas law:  P1V1/T1 = P2V2/T2,

where the subscripts are the initial (1) and final (2) states.  Temperature must be in Kelvin.  We want P2, so rearrange the equation to solve for P2:

P2 = P1(V1/V2)(T2/T1)

Note how I've arranged the volume and temperature values:  as ratios.  Now it is easy to cancel units and see what is going to happen to the pressure if we lower the temperature.  Since the pressure change is a function of (T2/T1), and we are lowering the temperature (T2), we'd expect this to decrease the pressure.

No information is given on volume, so we'll assume a convenient value of 1 liter.  Now enter the data:

P2 = (0.917atm)*(1)*(322K/344K)

P2 = 0.858 atm

8 0
3 years ago
Which of the following is true about the Lewis structure of NF3? Really need help
Ganezh [65]

Answer:

All of the above.

Explanation:

Hello there!

In this case, according to the definition of the Lewis structures, which are represented by the valence electrons, we first identify that the N atom has five valence electrons and each fluorine has seven valence electrons.

In such a way, we cans say that N is the central atom due to its lower electronegativity, the molecule has 7+7+7+5=26 valence electrons and the three F-N bonds are covalent, therefore the answer is all of the above.

Regards!

7 0
3 years ago
The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with
Alexus [3.1K]

Answer:

20.2 kJ

Explanation:

Based on the information in the reaction, the amount of heat released per mole of Na₂O₂ (the molar enthalpy) is calculated as follows:

126 kJ / 2 mol = 63 kJ/mol Na₂O₂

The number of moles in 25.0g of Na₂O₂ must be calculated using the molecular weight of Na₂O₂ (77.978 g/mol):

(25.0 g)/(77.978 g/mol) = 0.32060 mol Na₂O₂

Thus, the heat released will be:

(63 kJ/mol)(0.32060 mol) = 20.2 kJ

6 0
4 years ago
Read 2 more answers
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