In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.
As, Moles is given as,
Moles = Mass / M.mass
Moles = 0.53 g ÷ 283.88 g.mol⁻¹
Moles = 0.00186 moles
Now calculate the number of Molecules present in calculated moles of P₂O₅.
As,
1 Mole of P₂O₅ contains = 6.022 × 10²³ Molecules
So,
0.00186 Moles of P₂O₅ contain = X Molecules
Solving for X,
X = (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol
X = 1.12 × 10²¹ Molecules
Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....
= 1.12 × 10²¹ × 7
= 7.84 × 10²¹ Atoms
Result:
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.
Answer:
The p orbital is a lobed region describing where an electron can be found, within a certain degree of probability. All p orbitals have l = 1, with three possible values for m (-1, 0, +1).
Explanation:
The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
Answer:
Chemicals in fertilizers run off into water and cause algae blooms
Explanation:
Of the answer choices, the ones that have to do with commercial land use are the ones discussing fertilizers. Some commercial land is dedicated to lawn, but commercial farms are a much larger portion of commercial land use. The appropriate choice is, "Chemicals in fertilizers run off into water and cause algae blooms."
