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Kryger [21]
3 years ago
8

Use the simplest rule you can find to calculate the next three terms of the following sequence. 8, 3, 0, –1, 0, . . . a. 0, 0, 0

c. 3, 8, 15 b. –1, 0, 8 d. -3, -6, -8
Mathematics
1 answer:
Luba_88 [7]3 years ago
7 0
Rule: second differences are 2.

Selection C is appropriate.

_____
First differences are the sequence of differences of the given numbers:
.. 3 -8 = -5
.. 0 -3 = -3
.. -1 -0 = -1
.. 0 -(-1) = 1
Second differences are the sequence of differences of these:
.. -3 -(-5) = 2
.. -1 -(-3) = 2
.. 1 -(-1) = 2
All of these are 2, so the sequence can be described by a *second* order polynomial (because *second* differences are a non-zero constant).
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Identify the graph of 3x^2+y^2=9 for T(-1,3) and write an equation of the translated or rotated graph in general form.
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ANSWER

D. Ellipse;

3{x}^{2}  +{y}^{2}  + 6x   - 6y + 3= 0

EXPLANATION

The given equation is

3 {x}^{2}  +  {y}^{2}  = 9

Dividing through by 9 gives

\frac{ {x}^{2} }{ 3}  +  \frac{ {y}^{2} }{9}  = 1

This is the equation of an ellipse centered at the origin.

If this ellipse has been translated, so that its center is now at (-1,3), then the equation of the translated ellipse becomes

\frac{ {(x + 1)  }^{2} }{ 3}  +  \frac{ {(y - 3)}^{2} }{9}  = 1

We multiply through by 9 to get,

3 {(x + 1)}^{2}  +  {(y - 3)}^{2}  = 9

Expand to obtain;

3( {x}^{2}  + 2x + 1) +  {y}^{2}  - 6y + 9 = 9

Expand to obtain;

3{x}^{2}  + 6x + 3+  {y}^{2}  - 6y + 9 = 9

Regroup and equate to zero to obtain;

3{x}^{2}  +{y}^{2}  + 6x   - 6y + 3= 0

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