See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer:
I don't know I'm sorry I tried to found answers but I couldn't
<span>To figure the amount of tropical fish in the aquarium you multiple length*height*width to find the cubic centimeters of the tank, then divide that number by 10,000. 60*50*30=90,000 cubic centimeters. 90,000/10,000=9. 9 tropical fish could be places in a tank with those dimensions.</span>
.05*3= .15
4000*.15= 600 So 600 people left the town
Now subtract
4000-600= 3400
Angles of a triangle add up to 180 degrees and then we take away the right angle
180-90=90
5x+5x=10x
90/10=9
x=9
