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algol13
4 years ago
6

Which expression has a positive value?

Mathematics
1 answer:
Leokris [45]4 years ago
3 0

Answer:

im pretty sure C. 3(-64-8) + 25 will give you a positive value

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Find the area of a circle with a diameter of 8 in. Rounded to the nearest tenth. Use 3.14 for π.
rodikova [14]

Answer:

50.2 in^2

Step-by-step explanation:

Using the Formula

A=πr2

d=2r

Solving for A

A= 1/4 π d^2 = 1/4*π*8^2 = 50.26548

=50.2in^2

7 0
3 years ago
Which expression is equivalent to 4'7 × 4-5​
inna [77]

Answer:

2.7 x 5-6

Step-by-step explanation:

4 0
3 years ago
15) Victor drove 520 miles in 8 hours. At this rate how long will it take him to travel
nevsk [136]

Answer:17hrs

Step-by-step explanation:

520/8=65

1105/65

17

6 0
3 years ago
Which polynomial would produce the following graph? y = x(x - 1)(x + 2) y = -x(x - 1)(x + 2) y = x(x - 1)(x - 2) y = -x(x - 1)(x
Alecsey [184]
The correct answer is <span>y = -x(x - 1)(x + 2).</span>
7 0
3 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
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